J & K CET Medical J & K - CET Medical Solved Paper-2014

  • question_answer
    A 15pF capacitor is connected to a 60 V battery. How much electrostatic energy is stored?

    A)  \[2.77\times {{10}^{-8}}J\]

    B)  \[1.77\times {{10}^{-8}}J\]

    C)  \[2.35\times {{10}^{-8}}J\]

    D)  \[1.35\times {{10}^{-8}}J\]

    Correct Answer: A

    Solution :

     Electrostatic energy \[U=\frac{1}{2}C{{V}^{2}}\] \[=\frac{1}{2}(15\times {{10}^{-12}})\times {{(60)}^{2}}\] \[=\frac{1}{2}\times 15\times 36\times {{10}^{-12}}\times {{10}^{2}}\] \[=270\times {{10}^{-10}}=2.70\times {{10}^{-8}}J\]


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