A) \[3:16\]
B) \[16:9\]
C) \[3:4\]
D) \[4:3\]
Correct Answer: B
Solution :
\[Power=\frac{{{V}^{2}}}{R}\] As V is same for both bulbs, so, Power \[\propto \frac{1}{R}\]so Intensity \[\propto \frac{1}{R}\] \[\Rightarrow \]So, \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{16}{9}\]
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