A) \[5.55\times {{10}^{-3}}{}^\circ C\]
B) \[7.55\times {{10}^{-3}}{}^\circ C\]
C) \[11.75\times {{10}^{-2}}{}^\circ C\]
D) \[15.5\times {{10}^{-3}}{}^\circ C\]
Correct Answer: B
Solution :
\[{{R}_{2}}={{R}_{1}}[1+\alpha ({{T}_{2}}-{{T}_{1}})]\] \[\frac{({{R}_{2}}-{{R}_{1}})}{({{T}_{2}}-{{T}_{1}})}\times \frac{1}{{{R}_{1}}}=\alpha \] \[\frac{(2.5-1.6)}{(100-25.5)}\times \frac{1}{1.6}=\alpha \] \[\frac{0.9}{74.5}\times \frac{1}{1.6}=\alpha \] \[0.0075503=\alpha \] \[\alpha =7.55\times {{10}^{-3}}{}^\circ C\]
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