A) 2.10V
B) 2.94V
C) 1.50V
D) 1.20V
Correct Answer: B
Solution :
For equating emf of two cells \[\frac{{{e}_{1}}}{{{e}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\] \[\frac{2.1}{E}=\frac{40}{56}\] \[E=\frac{2.1\times 56}{40}=2.94V\]You need to login to perform this action.
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