J & K CET Medical J & K - CET Medical Solved Paper-2014

  • question_answer
    The angle of a prism is\[42{}^\circ \]and refractive index of its material is 3/2. Then, angle of minimum deviation for this prism is

    A)  \[63{}^\circ \]   

    B)  \[42{}^\circ \]    

    C)  \[28{}^\circ \]    

    D)  \[21{}^\circ \]

    Correct Answer: D

    Solution :

     Angle of minimum deviation \[{{\delta }_{\min }}=(\mu -1)A\] \[=\left( \frac{3}{2}-1 \right)42{}^\circ \] \[=\frac{1}{2}\times 42\] \[=21{}^\circ \]


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