A) 0.012 T
B) 0.120 T
C) 1.200 T
D) 2.10 T
Correct Answer: A
Solution :
\[m=8.7\times {{10}^{-2}}A-{{m}^{2}}\] \[l=11.5\times {{10}^{-6}}kg-{{m}^{2}}\] \[T=0.67s\] \[\Rightarrow \]From the formula \[T=2\pi \sqrt{\frac{l}{mB}}\Rightarrow B=\frac{4{{\pi }^{2}}\times l}{m{{T}^{2}}}\] \[=\frac{453.5\times {{10}^{-6}}}{{{10}^{-2}}\times 3.9}=116.28\times {{10}^{-4}}\] \[=0.0116=0.012T\]
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