A) 2
B) 1.5
C) 2.5
D) 0
Correct Answer: B
Solution :
Number of electrons in \[O_{2}^{-}=8+8+1=17\] MO configuration of\[O_{2}^{-}=\sigma 1{{s}^{2}},{{\sigma }^{*}}1{{s}^{2}},\sigma 2{{s}^{2}},{{\sigma }^{*}}2{{s}^{2}},\] \[\sigma 2p_{z}^{2},\pi 2p_{x}^{2}\] \[\approx \pi 2p_{y}^{2},{{\pi }^{*}}2p_{x}^{2}\approx {{\pi }^{*}}2p_{y}^{1}\] Here,\[{{N}_{b}}\](bonding electrons) =10 \[{{N}_{a}}\] (antibonding electrons) =7 \[\because \] \[Bond\text{ }order=\frac{{{N}_{b}}-{{N}_{a}}}{2}\] \[\therefore \] \[Bond\text{ }order=\frac{10-7}{2}=15\]
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