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J & K CET Medical J & K - CET Medical Solved Paper-2015

  • question_answer
    \[\frac{{{K}_{p}}}{{{K}_{C}}}\]for the reaction \[A(g)+2{{B}_{2}}(g)\xrightarrow{{}}A{{B}_{2}}(g)\]is

    A)  \[RT\]

    B)  \[{{(RT)}^{2}}\]

    C)  \[\frac{1}{RT}\]

    D)  \[\frac{1}{{{(RT)}^{2}}}\]

    Correct Answer: D

    Solution :

     \[A(g)+2B(g)\xrightarrow{{}}A{{B}_{2}}(g)\] \[{{K}_{P}}={{K}_{C}}(RT)_{g}^{\Delta n}\] \[\Delta {{n}_{g}}=\]change in number of moles = moles of product - moles of-reactant \[=1-3=-2\] \[\therefore \] \[{{K}_{P}}={{K}_{C}}{{(RT)}^{2}}\] \[\Rightarrow \] \[\frac{{{K}_{p}}}{{{K}_{C}}}=\frac{1}{{{(RT)}^{2}}}\]


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