A) 0.5
B) 2
C) 16
D) 4
Correct Answer: C
Solution :
\[C(s)+C{{O}_{2}}(g)\xrightarrow[{}]{{}}2CO(g)\] Applying the law of mass action \[{{K}_{p}}=\frac{{{({{p}_{CO}})}^{2}}}{({{p}_{C}})({{p}_{C{{O}_{2}}}})}\] Given, \[{{p}_{CO}}=8\,atm\] \[{{p}_{C{{O}_{2}}}}=4\,atm\] and for solid\[C(s)\] \[{{P}_{C}}=1\] \[\therefore \] \[{{K}_{p}}=\frac{{{(8)}^{2}}}{1\times 4}\] \[\Rightarrow \] \[{{K}_{p}}=\frac{64}{4}=16\]You need to login to perform this action.
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