A) zero
B) less than\[f\]
C) equal to\[f\]
D) more than\[f\]
Correct Answer: B
Solution :
We know that for a mirror \[\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\] For convergent u is positive. For concave mirror\[f\]negative \[\Rightarrow \] \[\frac{1}{v}=-\frac{1}{u}-\frac{1}{f}\] As, \[u>>f\] \[\Rightarrow \] \[\left[ \frac{1}{v}>\frac{1}{f} \right]\Rightarrow v<f\]
You need to login to perform this action.
You will be redirected in
3 sec
