A) remain stationary at origin\[O\]
B) move along positive X-axis
C) move along negative X-axis
D) undergo a circular motion in the\[X-Y\]plane
Correct Answer: A
Solution :
The particle is released from rest, i.e.\[v=0\]. Force on the particle due to magnetic field \[F=qvB=q(0)B=0\] Therefore, particle remains stationary at the origin.You need to login to perform this action.
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