A) \[PA=PB\]
B) \[{{t}_{A}}={{t}_{B}}\]
C) \[{{V}_{A}}>{{V}_{B}}\]
D) ball A hits the ground at an angle\[(-\theta )\]with horizontal
Correct Answer: C
Solution :
Consider, the two projectiles projected from\[O\] and P as shown in the figure. Range of both the particles \[R=\frac{{{v}^{2}}\sin 2\theta }{g}\] \[\Rightarrow \] \[OQ=PB=R\] Clearly, velocity at the points A/ and B will be same. Velocity of the ball following the trajectory OCA will increase after A due to accelerated motion under gravity. Therefore, we can say that\[{{v}_{A}}>{{v}_{B}}\]You need to login to perform this action.
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