A) only less than \[45{}^\circ \]
B) only greater than\[45{}^\circ \]
C) any value in the range\[0{}^\circ \]to\[90{}^\circ \]except\[45{}^\circ \]
D) any value in the range\[0{}^\circ \]to\[90{}^\circ \]including\[45{}^\circ \]
Correct Answer: C
Solution :
Brewsters angle corresponding to two media of refractive indices\[{{r}_{1}}\]and\[{{r}_{2}}\]is \[\tan {{i}_{B}}=\left( \frac{{{n}_{2}}}{{{n}_{1}}} \right)\] where,\[{{n}_{2}}\]is refractive index of denser medium and\[{{n}_{1}}\]is refractive index of rarer medium. If two mediums are same, i.e. \[{{n}_{1}}={{n}_{2}}\Rightarrow \tan {{i}_{B}}=1\]or\[{{i}_{B}}=45{}^\circ \] Polarisation is not possible if two mediums are same. Therefore\[{{i}_{B}}\ne 45{}^\circ \] Hence, Brewsters angle can have any value in the range\[0{}^\circ \]to\[90{}^\circ \]except\[45{}^\circ \].You need to login to perform this action.
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