A) 40kJ
B) 140kJ
C) 90 kJ
D) 50 kJ
Correct Answer: A
Solution :
Given, \[{{E}_{f}}=90\,kJ\] \[{{E}_{b}}=?\] \[\Delta H=50\,kJ\] \[\Delta H={{E}_{f}}-{{E}_{b}}\] \[50=90-{{E}_{b}}\] \[{{E}_{b}}=(90-50)kJ\] \[{{E}_{b}}=40\,kJ\]You need to login to perform this action.
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