A) 2.0 A
B) 2.5 A
C) 3.0 A
D) 3.5 A
Correct Answer: B
Solution :
Given, \[L=1\text{ }m,\text{ }N=1000\] Number of turns per unit length \[n=\frac{N}{L}=\frac{1000}{1}=1000\] Magnetic field inside a long selenoid \[B={{\mu }_{0}}nI\] \[\Rightarrow \] \[3.14\times {{10}^{-3}}=4\times 314\times {{10}^{-7}}\times 1000\times I\] \[\Rightarrow \] \[10=4\times I\] \[\Rightarrow \] \[I=2.5\,A\]
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