A) 4
B) 6
C) 8
D) 10
Correct Answer: C
Solution :
Original frequency of whistle \[{{v}_{0}}=272\,Hz\] Speed of the person,\[v=18\text{ }km/h=5\text{ }m/s\] Speed of sound, \[v=345\text{ }m/s\] Observed apparent frequency of reflecting surface \[{{v}_{a}}=\left( \frac{v}{v-{{v}_{s}}} \right){{v}_{0}}\] \[=\left( \frac{345}{345-5} \right)272=\frac{345}{340}\times 272\] Observed apparent frequency by the person, considering the reflecting surface as source. \[v_{a}^{}=\left( \frac{v+{{v}_{0}}}{v} \right){{v}_{a}}\] \[=\left( \frac{345+5}{345} \right)\left( \frac{345}{340} \right)\times 272\] \[=\left( \frac{350}{340} \right)\times 272=\frac{35}{34}\times 272\] \[=35\times 8=280\text{ }Hz\] Thus, number of beats beared by the person is \[v=v_{a}^{}-{{v}_{0}}=280-272=8\]You need to login to perform this action.
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