A) \[mg\,\cos \theta \]
B) \[mmg\,\cos \theta \]
C) \[mg\,\sin \theta \]
D) \[mmg\,\sin \theta \]
Correct Answer: C
Solution :
Suppose a force F is acting on the block as shown in the figure. Minimum value of the force required to just move the block up is \[{{F}_{\min }}=mgsin\theta +{{f}_{\min }}\] where, \[f=\]frictional force \[{{f}_{\min }}=0\] \[\Rightarrow \] \[{{F}_{\min }}=mg\sin \theta \]You need to login to perform this action.
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