A) \[0.\text{1 J}\]
B) \[\alpha \]
C) \[\text{3}.\text{4}\times \text{1}{{0}^{-\text{14}}}\text{ m}\]
D) \[(e=1.6\times {{10}^{-19}}C)\]
Correct Answer: C
Solution :
Using the formula for total intensity \[C{{H}_{3}}COOH:\] \[C{{H}_{3}}CHO\] \[C{{O}_{2}}\]You need to login to perform this action.
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