JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2004

  • question_answer
        99th     term     of     the     series\[\theta \]is :

    A)  9998                                     

    B)  9999

    C)  10000                                  

    D)  100000

    Correct Answer: A

    Solution :

                    Let \[S=2+7+14+23+34+...\text{ }+{{T}_{n}}\]     ...(i) arid \[S=2+7+14+23+34+...{{T}_{n-1}}+{{T}_{n}}\]...(ii) from equation (i) and (ii), we get \[S-S=2+[5+7+9+11+.....\] \[+{{T}_{n}}-{{T}_{n-1}}]-{{T}_{n}}\] \[\Rightarrow \]               \[{{T}_{n}}=2+\left[ \frac{n+1}{2}\{2\times 5+(n-2)2\} \right]\] \[\Rightarrow \]               \[{{T}_{n}}=2+(n-1)(n+3)\]                     ...(iii) now put \[n=99\] \[\Rightarrow \]\[{{T}_{99}}=2+98\times 102=9998\]                


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