A) \[{{(x-2)}^{3}}+27=0\]
B) \[-1,-1,-1\]
C) \[-1,-\omega ,-{{\omega }^{2}}\]
D) \[-1,2+3\omega ,2+3{{\omega }^{2}}\]
Correct Answer: B
Solution :
\[\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{n(n+1)}\] \[=\left( \frac{1}{1}-\frac{1}{2} \right)+\left( \frac{1}{2}-\frac{1}{3} \right)+...\left( \frac{1}{n}-\frac{1}{n+1} \right)\] \[=1-\frac{1}{n+1}=\frac{n+1-1}{n+1}=\frac{n}{n+1}\]
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