A) \[(-1,0)\]
B) \[\left( 0,1 \right)\]
C) \[\left( 0,-\text{l} \right)\]
D) \[{{x}^{2}}-4x-4y+4=0\]
Correct Answer: A
Solution :
\[\theta ={{\cos }^{-1}}\left[ \frac{3+0-5}{\sqrt{1+1}\sqrt{9+16+25}} \right]\]\[={{\cos }^{-1}}\left( \frac{-2}{10} \right)\] \[\left[ \because \cos \theta =\frac{a{{a}_{1}}+b{{b}_{1}}+c{{c}_{1}}}{\sqrt{{{a}^{2}}+{{b}^{2}}{{c}^{2}}}\sqrt{a_{1}^{2}+b_{1}^{2}+c_{1}^{2}}} \right]\]\[={{\cos }^{-1}}\left( \frac{1}{5} \right)\]
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