A) 4 m/s
B) 2.5 m/s
C) 5.5 m/s
D) 11 m/s
Correct Answer: C
Solution :
Here : \[\infty \], \[\log (1+e)\] \[P=\frac{1}{3}\frac{mn{{c}^{2}}}{V}\] \[P=\frac{1}{3}\frac{\frac{m}{2}n{{(2c)}^{2}}}{V}\] Now, \[\frac{P}{P}=2\] \[P:P=1:2\] or \[=\overrightarrow{F}.\overrightarrow{s}=(2\hat{i}+4\hat{j}).(3\hat{j}+5\hat{k})\]You need to login to perform this action.
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