A) 0.325
B) 0.0325
C) 0.98
D) 0.968
Correct Answer: B
Solution :
Here : \[\text{C}{{\text{H}}_{\text{3}}}\text{N}{{\text{H}}_{\text{2}}}\] SO, \[\text{C}{{\text{H}}_{\text{3}}}\text{CHO}\] \[{{\text{H}}_{\text{2}}}\text{O}\] \[\text{A}{{\text{g}}^{+}}\] From \[\text{N}{{\text{H}}_{\text{3}}}\] \[O{{H}^{-}}\] \[{{N}_{2}}{{O}_{4}}\xrightarrow{{}}2N{{O}_{2}}\]You need to login to perform this action.
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