A) 6480 km/s
B) 3240 km/s
C) 4240 km/s
D) none of these
Correct Answer: A
Solution :
Here: \[{{\lambda }_{0}}\]= 393.3 nm \[\lambda \]= 401.8 nm Red shift,\[z=\frac{\lambda -{{\lambda }_{0}}}{{{\lambda }_{0}}}\] \[=\frac{401.8-393.3}{393.3}\] \[=\frac{8.5}{393.3}=0.0216\] Now \[z=\frac{\upsilon }{c}\]then \[\upsilon =zc=0.0216\times 3\times {{10}^{8}}\] \[=6.48\times {{10}^{6}}m/s\] \[=6480km/s\]You need to login to perform this action.
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