A) Pepsin
B) Adrenaline
C) ATP
D) Glutamin
Correct Answer: A
Solution :
We know that, \[\lambda =\frac{0.693}{{{t}_{1/2}}}\] \[{{t}_{1/2}}=\frac{0.693}{2.31\times {{10}^{-4}}}\] \[=3\times {{10}^{3}}years\]You need to login to perform this action.
You will be redirected in
3 sec