question_answer

    The displacement time graph for two bodies A and B are straight lines inclined at 30° and 60° respectively with the time axes. If \[\upsilon =\sqrt{4rg}\] and \[\upsilon =\sqrt{4\times 2.5\times 9.8}\] are their velocities, then \[\upsilon =\sqrt{98}\,\,m/s\]will be :

A)  \[\text{2}0\text{ g }=\text{ 2}\times \text{1}{{0}^{-\text{2}}}\text{ kg},\]                           

B)  \[=\frac{360\times 5}{18}=100m/s\]

C)  3 : 1                                      

D)  1 : 3

Correct Answer: D

Solution :

                Here :     \[=12j\]               ...(1) \[=\frac{work}{time}=\frac{12}{2}\]                        ...(2) \[=\text{6 watt}\] \[{{s}_{1}}=40m,{{s}_{2}}=65m\]