A) \[90{}^\circ \]
B) \[60{}^\circ \]
C) \[45{}^\circ \]
D) \[30{}^\circ \]
Correct Answer: D
Solution :
Using the relation \[3\times {{10}^{-3}}\Omega \] Or \[\text{8}.\text{1}0\times \text{1}{{0}^{-\text{5}}}\text{ }\Omega \] Or \[\text{4}.0\text{5}\times \text{1}{{0}^{-\text{6}}}\text{ }\Omega \] \[\text{1}\text{.35}\times \text{1}{{0}^{-8}}\text{ }\Omega \] Or \[2.70\times \text{1}{{0}^{-7}}\Omega \]
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