question_answer

    The radius of nucleus of silver (atomic number = 47) is\[\text{8}.\text{1}0\times \text{1}{{0}^{-\text{5}}}\text{ }\Omega \]. The electric potential on the surface of nucleus is : \[\text{4}.0\text{5}\times \text{1}{{0}^{-\text{6}}}\text{ }\Omega \]

A) \[\text{1}\text{.35}\times \text{1}{{0}^{-8}}\text{ }\Omega \]  

B)  \[2.70\times \text{1}{{0}^{-7}}\Omega \]

C) \[2\mu F\]         

D)  \[0.00\text{1 J}\]