A) \[=\frac{n\times \frac{1}{2}m{{\upsilon }^{2}}}{t}\]
B) \[=\frac{360\times \frac{1}{2}\times 2\times {{10}^{-2}}\times {{(100)}^{2}}}{60}\]
C) \[g=\frac{Gm}{{{R}^{2}}}\]
D) \[\overrightarrow{\text{F}}=\left( \text{2\hat{i}}+\text{4\hat{j}} \right)\]
Correct Answer: A
Solution :
According to kinetic interpretation of temperature \[{{t}_{1}}=5s,a=?\] Given : \[a=\frac{{{s}_{2}}-{{s}_{1}}}{{{t}^{2}}}=\frac{65-40}{{{(5)}^{2}}}\] So, \[=\frac{25}{25}=1m/{{s}^{2}}\] Or \[{{s}_{1}}=ut+\frac{1}{2}a{{t}^{2}}\] \[40=5u+\frac{1}{2}\times 1\times 25\] \[5u=27.5\,\,or\,\,\,u=5.5m/s\]
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