A) 3
B) 2
C) 1
D) zero
Correct Answer: D
Solution :
\[l=A{{R}^{n-1}}\Rightarrow \log l=\log A+(p-1)\log R\] \[m=A{{R}^{n-1}}\Rightarrow \log m=\log A+(q-1)\log R\] \[n=A{{r}^{r-1}}\Rightarrow \log n=\log A+(r-1)\log R\] Now, \[\left| \begin{matrix} \log l & p & 1 \\ \log m & q & 1 \\ \log & r & 1 \\ \end{matrix} \right|=\left| \begin{matrix} \log A+(p-1)\log R & p & 1 \\ \log A+(q-1)\log R & q & 1 \\ \log A+(r-1)\log R & r & 1 \\ \end{matrix} \right|=0\]You need to login to perform this action.
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