A) \[z\hat{j}-x\hat{k}\]
B) \[\overrightarrow{0}\]
C) \[y\hat{j}\]
D) \[-z\hat{i}+x\hat{k}\]
Correct Answer: A
Solution :
Since,\[\overrightarrow{a},\text{ }\overrightarrow{c},\text{ }\overrightarrow{b}\] form a right handed system, therefore, \[\overrightarrow{c}\,\text{= }\overrightarrow{b}\times \overrightarrow{a}\] \[=\left| \begin{matrix} {\hat{i}} & {\hat{j}} & {\hat{k}} \\ 0 & 1 & 0 \\ x & y & z \\ \end{matrix} \right|\] \[=z\hat{i}-x\hat{k}\]You need to login to perform this action.
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