A) \[x+y=2\]
B) \[x+y=2\sqrt{2}\]
C) \[x+y=4\]
D) \[x+y=8\]
Correct Answer: B
Solution :
Let the equation of the required tangent be\[x+y=a\]then, length of the perpendicular from centre = radius\[\left| \frac{-2+2-a}{\sqrt{2}} \right|=2\]\[\Rightarrow \]\[a=2\sqrt{2}\] Hence, the equation of tangent is\[x+y=2\sqrt{2}\]You need to login to perform this action.
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