A) \[[1,9]\]
B) \[[-1,9]\]
C) \[[-9,1]\]
D) \[[-9,-1]\]
Correct Answer: A
Solution :
\[f(x)={{\sin }^{-1}}\left( {{\log }_{3}}\left( \frac{x}{3} \right) \right)\]exists if \[-1\le {{\log }_{3}}\left( \frac{x}{3} \right)\le 1\]\[\Leftrightarrow \]\[{{3}^{-1}}\le \frac{x}{3}\le {{3}^{1}}\] \[\Leftrightarrow \]\[1\le x\le 9\]\[\Leftrightarrow \]domain is [1, 9]You need to login to perform this action.
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