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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        The solution of the equation\[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{e}^{-2x}}\]is:

    A)  \[\frac{{{e}^{-2x}}}{4}\]                              

    B)  \[\frac{{{e}^{-2x}}}{4}+cx+d\]

    C)  \[\frac{1}{4}{{e}^{-2x}}+c{{x}^{2}}+d\] 

    D)  \[\frac{1}{4}{{e}^{-2x}}+c+d\]

    Correct Answer: B

    Solution :

                                     \[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{e}^{-2x}}\] \[\frac{dy}{dx}=\frac{{{e}^{-2x}}}{-2}+c\] \[y=\frac{{{e}^{-2x}}}{4}+cx+d\]


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