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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        On moving a charge of 20 coulombs by 2 cm, 2 J of work is done, then the potential difference between the points is:

    A)  0.1 V                                    

    B)  8 V

    C)  2 V                                        

    D)  0.5 V

    Correct Answer: A

    Solution :

                    Potential difference between two points in a electric field is, \[{{V}_{A}}-{{V}_{B}}=\frac{W}{{{q}_{0}}}\]where W is work done by moving charge\[{{q}_{0}}\]from point A to B. So,          \[{{V}_{A}}-{{V}_{B}}=\frac{2}{20}\] (Here: \[W=25,\]\[{{q}_{0}}=20C\]) \[=0.1V\]


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