A) \[\frac{1}{8}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{2}\]
D) \[\frac{2}{3}\]
Correct Answer: B
Solution :
Required probability \[P(A{{ & }_{1}}A_{2}^{}{{A}_{3}})+P(A_{1}^{},{{A}_{2}},{{A}_{3}})\] \[=P({{A}_{1}})P(A_{2}^{})P({{A}_{3}})+P(A_{1}^{})P({{A}_{2}})P({{A}_{3}})\] \[={{\left( \frac{1}{2} \right)}^{3}}+{{\left( \frac{1}{2} \right)}^{3}}\] \[=\frac{1}{8}+\frac{1}{8}\] \[=\frac{2}{8}\] \[=\frac{1}{4}\]You need to login to perform this action.
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