A) 10
B) 20
C) 25.5
D) 5
Correct Answer: B
Solution :
As, \[P.E.=K.E.\] \[mgh=\frac{1}{2}m{{v}^{2}}\] \[v=\sqrt{2gh}\] \[=\sqrt{2\times 10\times 20}\] [Here:\[g=10\,m/{{s}^{2}}\]] \[=20\text{ }m/s\]You need to login to perform this action.
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