A) a proton changes to neutron
B) a neutron changes to proton
C) a neutron changes to electron
D) an electron changes to neutron
Correct Answer: B
Solution :
\[_{0}^{1}n\xrightarrow[{}]{{}}_{1}^{1}H+_{-1}^{0}e(\beta )\]You need to login to perform this action.
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