A) \[1:2\]
B) \[1:4\]
C) \[2:1\]
D) \[4:1\]
Correct Answer: C
Solution :
Let the tubes A and B have equal length called as\[l\]. Since, tube A is opened at both the ends, therefore, its fundamental frequency \[{{n}_{A}}=\frac{v}{2l}\] ...(1) Since, tube B is closed at one end, therefore, its fundamental frequency \[{{n}_{B}}=\frac{v}{4l}\] ...(2) From eqs. (1) and (2), we get \[\frac{{{n}_{A}}}{{{n}_{B}}}=\frac{\frac{v}{2l}}{\frac{v}{4l}}\] \[=\frac{4}{2}=2:1\]You need to login to perform this action.
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