A) \[{{N}_{0}}/8\]
B) \[{{N}_{0}}/16\]
C) \[{{N}_{0}}/2\]
D) \[{{N}_{0}}/4\]
Correct Answer: A
Solution :
\[{{N}_{0}}\] is the initial amount of substance and N is the amount left after decay. Thus, \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] n = no. of half lives\[=\frac{t}{{{t}_{1/2}}}\] \[=\frac{15}{5}=3\] Therefore, \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{3}}\] \[=\frac{{{N}_{0}}}{8}\]
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