A) \[CV\]
B) \[\frac{1}{2}nC{{V}^{2}}\]
C) \[C{{V}^{2}}\]
D) \[\frac{1}{2n}C{{V}^{2}}\]
Correct Answer: B
Solution :
Energy stored by any system of capacitors is \[=\frac{1}{2}{{C}_{net}}{{V}^{2}}\]where V is source voltage Thus, n capacitors are connected in parallel. Therefore, \[{{C}_{net}}=nC\] \[\therefore \] \[{{E}_{net}}=\frac{1}{2}nC{{V}^{2}}\]
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