JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        A lift is moving down with acceleration a. Aman in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively:

    A)  \[g,g\]

    B)  \[g-a.\text{ }g-a\]

    C)  \[g-a,g\]

    D)  \[a,g\]

    Correct Answer: C

    Solution :

                    Apparent weight of ball \[w=w-R\] \[R=ma\] acts upward\[=ma\] \[w=mg-ma=m(g-a)\] Hence, apparent acceleration in the lift is\[g-a\] Now if the man is standing stationary on the ground, then the apparent acceleration of the falling ball is g.


You need to login to perform this action.
You will be redirected in 3 sec spinner