A) 16 J
B) 8 J
C) 32 J
D) 24 J
Correct Answer: B
Solution :
The work is stored as the P.E. of the body and is given by, \[U=\int_{{{x}_{1}}}^{{{x}_{2}}}{{{F}_{external}}}dx\] Or \[U=\int_{{{x}_{1}}}^{{{x}_{2}}}{kx}\,dx\] \[=\frac{1}{2}k(x_{2}^{2}-x_{1}^{2})\] \[=\frac{800}{2}[{{(0.15)}^{2}}-{{(0.05)}^{2}}]\] \[[k=800(given)]\] \[=400[0.2\times 0.1]\] \[=8\,joule\]You need to login to perform this action.
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