A) \[M{{n}^{2+}}\]
B) \[F{{e}^{2+}}\]
C) \[T{{i}^{2+}}\]
D) \[C{{r}^{2+}}\]
Correct Answer: A
Solution :
\[M{{n}^{2+}}:(Ar)3{{d}^{5}}\]with five unpaired electrons hence maximum magnetic moment.
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