A) 1
B) 2
C) 1/2
D) 4
Correct Answer: A
Solution :
Magnetic field in circular coil A is Similarly \[{{B}_{A}}=\frac{{{\mu }_{0}}Ni}{2R}\] R is radius and i is current flowing in coil. \[{{B}_{B}}=\frac{{{\mu }_{0}}N(2i)}{2.(2R)}\] \[=\frac{{{\mu }_{0}}Ni}{2R}\] \[\frac{{{B}_{A}}}{{{B}_{B}}}=\frac{1}{1}=1\]You need to login to perform this action.
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