A) \[2\,\Omega \]
B) \[6\,\Omega \]
C) \[5\,\Omega \]
D) \[4\,\Omega \]
Correct Answer: B
Solution :
\[P=\frac{{{V}^{2}}}{{{R}_{net}}}\] \[150=\frac{{{(15)}^{2}}}{\frac{R.2}{2+R}}\] \[R=6\,ohm\]You need to login to perform this action.
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