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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        For an aqueous solution, freezing point is\[-0.186{}^\circ C\]. Elevation of the boiling point of the same solution is (\[{{K}_{f}}=1.86{}^\circ mo{{l}^{-1}}kg\]and \[{{K}_{f}}=0.512{}^\circ mo{{l}^{-1}}kg\]):

    A)  \[0.186{}^\circ \]            

    B)  \[0.0512{}^\circ \]

    C)  \[1.86{}^\circ \]                               

    D) \[5.12{}^\circ \]

    Correct Answer: B

    Solution :

                    \[\Delta {{T}_{b}}=m{{K}_{b}}\] \[\Delta {{T}_{f}}=m{{K}_{f}}\] \[\frac{\Delta {{T}_{b}}}{\Delta {{T}_{f}}}=\frac{{{K}_{b}}}{{{K}_{f}}}=\frac{0.512}{1.86}\] \[\Delta {{T}_{b}}=\frac{0.512}{1.86}\times 0.186\] \[=0.0512{}^\circ \]        


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