A) \[{{(RT)}^{1/2}}\]
B) \[{{(RT)}^{-1/2}}\]
C) \[(RT)\]
D) \[{{(RT)}^{-1}}\]
Correct Answer: A
Solution :
\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\] \[\Delta {{n}_{g}}=1-1.5=-0.5\] \[{{K}_{p}}={{K}_{c}}{{(RT)}^{-1/2}}=\frac{{{K}_{c}}}{{{(RT)}^{1/2}}}\] \[\therefore \] \[\frac{{{K}_{c}}}{{{K}_{p}}}={{(RT)}^{1/2}}\]You need to login to perform this action.
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