A) \[6.2\times {{10}^{-11}}\]
B) \[16\times {{10}^{-9}}\]
C) \[16\times {{10}^{-11}}\]
D) \[16\times {{10}^{-13}}\]
Correct Answer: C
Solution :
Robert Millikan performed the experiment to determine the charge on an electron. When a drop is suspended, its weight mg is exactly equal to the electric force applied qE, where E is electric filed, q the charge, m the mass of drop and g the acceleration due to gravity.You need to login to perform this action.
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