A) \[\text{9}\text{.90 }\Omega \] in series
B) \[\text{10 }\Omega \] in series
C) \[\text{990 }\Omega \] in series
D) \[\text{0}\text{.10 }\Omega \] in series
Correct Answer: C
Solution :
Let G be resistance of galvanometer and\[{{i}_{g}}\]the current through it. Let Vis maximum potential difference, then from Ohms lawYou need to login to perform this action.
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